The mean of five observations is 5 and their | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mu  = \frac{{1 + 3 + 8 + x + y}}{5}$

$25 = 12 + x + y \Rightarrow x + y = 13\,\,\,\,\,\,\,\,........\left( 1 \right)$

${\sigma ^2} = \fra

Vedclass · Accepted Answer

$4 : 9$

Vedclass · Answer

$\mu  = \frac{{1 + 3 + 8 + x + y}}{5}$

$25 = 12 + x + y \Rightarrow x + y = 13\,\,\,\,\,\,\,\,........\left( 1 ight)$

${\sigma ^2} = \frac{{\sum {{{\left( {{x_i} - \mu } ight)}^2}} }}{N}$

$9.2 = \frac{{1 + 9 + 64 + {x^2} + {y^2}}}{5} - 25$

$34.2 	imes 5 = 74 + {x^2} + {y^2}$

$171 = 74 + {x^2} + {y^2}$

$97 = {x^2} + {y^2}..........\left( 2 ight)$

${\left( {x + y} ight)^2} = {x^2} + {y^2} + 2xy$

$169 - 97 = 2xy \Rightarrow xy = 36$

$T = 4,9$

So, ratio is $\frac{4}{9}$ or $\frac{9}{4}$

The mean of five observations is $5$ and their variance is $9.20$. If three of the given five observations are $1, 3$ and $8$, then a ratio of other two observations is

Similar Questions

Find the mean and variance for the first $n$ natural numbers

If $M.D.$ is $12$, the value of $S.D.$ will be

For $(2n+1)$ observations ${x_1},\, - {x_1}$, ${x_2},\, - {x_2},\,.....{x_n},\, - {x_n}$ and $0$ where $x$’s are all distinct. Let $S.D.$ and $M.D.$ denote the standard deviation and median respectively. Then which of the following is always true

The means of five observations is $4$ and their variance is $5.2$. If three of these observations are $1, 2$ and $6$, then the other two are

Suppose values taken by a variable $x$ are such that $a \le {x_i} \le b$, where ${x_i}$ denotes the value of $x$ in the $i^{th}$ case for $i = 1, 2, ...n.$ Then..