The variance of the data 2, 4, 6, 8, 10 is | vedclass

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(c) Here, $\bar x = \frac{{2 + 4 + 6 + 8 + 10}}{5} = 6$

Hence, variance = $\frac{1}{n}\Sigma {({x_i} - \overline x )^2}$

$ = \frac{1}{5}\{ {(2 -

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(c) Here, $\bar x = \frac{{2 + 4 + 6 + 8 + 10}}{5} = 6$

Hence, variance = $\frac{1}{n}\Sigma {({x_i} - \overline x )^2}$

$ = \frac{1}{5}\{ {(2 - 6)^2} + {(4 - 6)^2} + {(6 - 6)^2} + {(8 - 6)^2} + {(10 - 6)^2}\} $

$ = \frac{1}{5}\left\{ {(16 + 4 + 0 + 4 + 16} \right\}$$ = \frac{1}{5}\left\{ {40} \right\}$ $ = 8$.

$x_i$	$2$	$4$	$6$	$8$	$10$	$12$	$14$	$16$
$f_i$	$4$	$4$	$\alpha$	$15$	$8$	$\beta$	$4$	$5$

${x_i}$	$6$	$10$	$14$	$18$	$24$	$28$	$30$
${f_i}$	$2$	$4$	$7$	$12$	$8$	$4$	$3$

The variance of the data $2, 4, 6, 8, 10$ is

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