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3 and 4 .Determinants and Matrices
hard
The number of $\theta \in(0,4 \pi)$ for which the system of linear equations
$3(\sin 3 \theta) x-y+z=2$, $3(\cos 2 \theta) x+4 y+3 z=3$, $6 x+7 y+7 z=9$ has no solution is.
A
$6$
B
$7$
C
$8$
D
$9$
(JEE MAIN-2022)
Solution
The system of equation has no solution.
$D=\left|\begin{array}{ccc}3 \sin 3 \theta & -1 & 1 \\3 \cos 2 \theta & 4 & 3 \\6 & 7 & 7\end{array}\right|=0$$21 \sin 3 \theta+42 \cos 2 \theta-42=0$$\sin 3 \theta+2 \cos 2 \theta-2=0$
Number of solution is $7$ in $(0,4 \pi)$
Standard 12
Mathematics