Gujarati
4-2.Quadratic Equations and Inequations
easy

समीकरण $|x{|^2} - 7|x| + 12 = 0$ के मूलों की संख्या है

A

$1$

B

$2$

C

$3$

D

$4$

Solution

(d) समीकरण $(|x| – 4)(|x| – 3) = 0$

$\Rightarrow$   $|x| = 4\,\, \Rightarrow x =  \pm 4$

$⇒|x| = 3\,\, \Rightarrow x =  \pm 3$.

Standard 11
Mathematics

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