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4-2.Quadratic Equations and Inequations
easy
The number of solutions for the equation ${x^2} - 5|x| + \,6 = 0$ is
A
$4$
B
$3$
C
$2$
D
$1$
Solution
(a) Given equation ${x^2} – 5|x| + 6 = 0$
i.e., ${x^2} – 5x + 6 = 0$ and ${x^2} + 5x + 6 = 0$
${x^2} – 3x – 2x + 6 = 0$ and ${x^2} + 3x + 2x + 6 = 0$
$(x – 3)\,(x – 2) = 0$ and $(x + 3)\,.\,(x + 2) = 0$
$x = 3,x = 2$ and $x = – 3,\,x = – 2$.
i.e., Four solutions of this equation.
Standard 11
Mathematics