1.Units, Dimensions and Measurement
easy

$g$ के मापन में हुई प्रतिशत न्रुटि है :(दिया है: $g =\frac{4 \pi^2 L }{ T ^2}, L =(10 \pm 0.1)\,cm$, $T =(100 \pm 1)\,s )$

A

$2$

B

$5$

C

$3$

D

$7$

(NEET-2022)

Solution

$g =\frac{4 \pi^2 L }{ T ^2}$

$\frac{\Delta g }{ g }=\frac{\Delta L }{ L }+2 \frac{\Delta T }{ T }$

$\%$ error in $g=\frac{0.1}{10} \times 100+2\left(\frac{1}{100}\right) \times(100)$

$=3 \%$

Standard 11
Physics

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