The photon energy in units of $eV$ for electromagnetic wave of wavelength $2\,cm$ is
$2.5 \times 10^{-19}$
$5.2 \times 10^{16}$
$3.2 \times 10^{-16}$
$6.2 \times 10^{-5}$
$TV$ waves have a wavelength range of $1-10 \,meter$. Their frequency range in $MHz$ is
A velocity selector consists of electric field $\overrightarrow{ E }= E \hat{ k }$ and magnetic field $\overrightarrow{ B }= B \hat{ j }$ with $B =12 mT$.
The value $E$ required for an electron of energy $728 eV$ moving along the positive $x$-axis to pass undeflected is:
(Given, , ass of electron $=9.1 \times 10^{-31} kg$ )
The electric field of a plane electromagnetic wave is given by $\overrightarrow{ E }= E _{0}(\hat{ x }+\hat{ y }) \sin ( kz -\omega t )$ Its magnetic field will be given by
An electromagnetic wave is represented by the electric field $\vec E = {E_0}\hat n\,\sin \,\left[ {\omega t + \left( {6y - 8z} \right)} \right]$. Taking unit vectors in $x, y$ and $z$ directions to be $\hat i,\hat j,\hat k$ ,the direction of propogation $\hat s$, is
About $5 \%$ of the power of a $100\; W$ light bulb is converted to visible radiation. What is the average intensity of visible radiation
$(a)$ at a distance of $1 \;m$ from the bulb?
$(b)$ at a distance of $10\; m ?$ Assume that the radiation is emitted isotropically and neglect reflection.