Gujarati
3 and 4 .Determinants and Matrices
easy

The product of a matrix and its transpose is an identity matrix. the value of determinant of this matrix is

A

$-1$

B

$0$

C

$ \pm {\rm{ }}1$

D

$1$

Solution

(c) Let $A = \left[ {\begin{array}{*{20}{c}}{ \pm 1}&0&0\\0&{ \pm 1}&0\\0&0&{ \pm 1}\end{array}} \right]$

and ${A^T} = \left[ {\begin{array}{*{20}{c}}{ \pm 1}&0&0\\0&{ \pm 1}&0\\0&0&{ \pm 1}\end{array}} \right]$

and $A{A^T} = \left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\0&0&1\end{array}} \right]$,

$\therefore \,\,|A|\,\, = \pm 1$.

Standard 12
Mathematics

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