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3 and 4 .Determinants and Matrices
easy
The product of a matrix and its transpose is an identity matrix. the value of determinant of this matrix is
A
$-1$
B
$0$
C
$ \pm {\rm{ }}1$
D
$1$
Solution
(c) Let $A = \left[ {\begin{array}{*{20}{c}}{ \pm 1}&0&0\\0&{ \pm 1}&0\\0&0&{ \pm 1}\end{array}} \right]$
and ${A^T} = \left[ {\begin{array}{*{20}{c}}{ \pm 1}&0&0\\0&{ \pm 1}&0\\0&0&{ \pm 1}\end{array}} \right]$
and $A{A^T} = \left[ {\begin{array}{*{20}{c}}1&0&0\\0&1&0\\0&0&1\end{array}} \right]$,
$\therefore \,\,|A|\,\, = \pm 1$.
Standard 12
Mathematics