The range of $f(x)=4 \sin ^{-1}\left(\frac{x^2}{x^2+1}\right)$ is
The range of $f(x)=4 \sin ^{-1}\left(\frac{x^2}{x^2+1}\right)$ is
- [JEE MAIN 2023]
- A
$[0, \pi]$
- B
$[0,2 \pi)$
- C
$[0, \pi)$
- D
$[0,2 \pi]$
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