1.Relation and Function
normal

વિધેય $f(x) = \frac{{x + 2}}{{|x + 2|}}$ નો વિસ્તાર મેળવો.

A

$\{0, 1\}$

B

$\{-1, 1\}$

C

$R$

D

$R - \{ - 2\} $

Solution

(b) $f(x) = \frac{{x + 2}}{{|x + 2|}}$

$f(x) = \left\{ {\begin{array}{*{20}{c}}{ – 1,}\\{\,\,1,}\end{array}} \right.\,\,\,\,\,\,\begin{array}{*{20}{c}}{x < – 2}\\{x > – 2}\end{array}$

$\therefore$ Range of $f(x)$ is $\{ – 1,\,1\} $.

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.