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11.Thermodynamics
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મુકતતાના અંશ $ ‘n’ $ ના સંદર્ભમાં વિશિષ્ટ ઉષ્મા $\frac{{{C_p}}}{{{C_V}}} = \gamma $ ને _______ વડે આપી શકાય.
A
$\left( {1 + \frac{1}{n}} \right)\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;$
B
$\;\left( {1 + \frac{n}{3}} \right)$
C
$\;\left( {1 + \frac{2}{n}} \right)$
D
$\;\left( {1 + \frac{n}{2}} \right)$
Solution
For $n$ degress of freedom, ${C_v} = \frac{n}{2}R$
Also, ${C_p} – {C_v} = R$
${C_P} = {C_v} + R = \frac{n}{2}R + R\left( {\frac{n}{2} + 1} \right)R$
$\gamma = \frac{{{C_P}}}{{{C_v}}} = \frac{{\left( {\frac{n}{2} + 1} \right)R}}{{\left( {n/2} \right)R}} = \frac{{n + 2}}{n}\,\,\,\therefore \,\,\,\gamma = 1 + \frac{2}{n}$
Standard 11
Physics
