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1.Relation and Function
medium
The relation $R$ is defined on the set of natural numbers as $\{(a, b) : a = 2b\}$. Then $\{R^{ - 1}\}$ is given by
A
$\{(2, 1), (4, 2), (6, 3).....\}$
B
$\{(1, 2), (2, 4), (3, 6)....\}$
C
${R^{ - 1}}$ is not defined
D
None of these
Solution
(b) $R = \{(2, 1), (4, 2), (6, 3),……\}.$
So, ${R^{ – 1}}$ $= \{(1, 2), (2, 4), (3, 6),…..\}.$
Standard 12
Mathematics