The solution of ${\log _{\sqrt 3 }}x + {\log _{\sqrt[4]{3}}}x + {\log _{\sqrt[6]{3}}}x + ......... + {\log _{\sqrt[{16}]{3}}}x = 36$ is
$x = 3$
$x = 4\sqrt 3 $
$x = 9$
$x = \sqrt 3 $
If ${a^{1/x}} = {b^{1/y}} = {c^{1/z}}$ and $a,\;b,\;c$ are in $G.P.$, then $x,\;y,\;z$ will be in
The sum of all two digit numbers which, when divided by $4$, yield unity as a remainder is
The sum of the numbers between $100$ and $1000$, which is divisible by $9$ will be
Three numbers are in $A.P.$ whose sum is $33$ and product is $792$, then the smallest number from these numbers is
If the sum of $n$ terms of an $A.P$. is $2{n^2} + 5n$, then the ${n^{th}}$ term will be