The solution of the equation ${\cos ^2}x - 2\cos x = $ $4\sin x - \sin 2x,$ $\,(0 \le x \le \pi )$ is
The solution of the equation ${\cos ^2}x - 2\cos x = $ $4\sin x - \sin 2x,$ $\,(0 \le x \le \pi )$ is
- A
$\pi - {\cot ^{ - 1}}\left( {\frac{1}{2}} \right)$
- B
$\pi - {\tan ^{ - 1}}(2)$
- C
$\pi + {\tan ^{ - 1}}\left( { - \frac{1}{2}} \right)$
- D
None of these
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