7.Binomial Theorem
easy

${(1 + x - 3{x^2})^{2163}}$ के विस्तार में गुणांकों का योग होगा

A

$0$

B

$1$

C

$ - 1$

D

${2^{2163}}$

(IIT-1982)

Solution

 $(1+x-3x^2 )^{2163}$.  मे $x=1$ रखने पर,

गुणांकों का योग =${(1 + 1 – 3)^{2163}} = {( – 1)^{2163}} =  – 1$.

Standard 11
Mathematics

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