Gujarati
8. Sequences and Series
easy

श्रेणी $9 - 3 + 1 - \frac{1}{3} + .....\infty$ का अनन्त पदों तक योगफल है

A

$9$

B

$9/2$

C

$27/4$

D

$15/2$

Solution

(c) दी गयी श्रेणी $9 – 3 + 1 – \frac{1}{3}……\infty $ अनन्त गुणोत्तर श्रेणी है,

जहाँ  $a = 9,r = \frac{{ – 1}}{3}$

 ${S_\infty } = \frac{a}{{1 – r}} = \frac{9}{{1 + \left( {\frac{1}{3}} \right)}} = \frac{{9 \times 3}}{4} = \frac{{27}}{4}$.

Standard 11
Mathematics

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