- Home
- Standard 11
- Mathematics
7.Binomial Theorem
easy
${\left[ {\sqrt{\frac{ x }{3}} + \frac{{\sqrt 3 }}{{{x^2}}}} \right]^{10}}$ ના વિસ્તરણમાં અચળપદ મેળવો.
A
$\frac{2}{3}$
B
$\frac{5}{3}$
C
$\frac{4}{3}$
D
એકપણ નહીં.
Solution
(b) Accordingly, ${(\sqrt x )^{10 – r}}{\left( {\frac{1}{{{x^2}}}} \right)^r} = {x^0} \Rightarrow r = 2$
Hence the term is $^{10}{C_2}{\left( {\frac{1}{{\sqrt 3 }}} \right)^8}.\,\,\,{(\sqrt 3 )^2} = \frac{5}{3}$.
Standard 11
Mathematics
