7.Gravitation
normal

The value of $g$ at the surface of earth is $9.8 \,m / s ^2$. Then the value of ' $g$ ' at a place $480 \,km$ above the surface of the earth will be nearly .......... $m / s ^2$ (radius of the earth is $6400 \,km$ )

A

$9.8$

B

 $7.2$

C

$8.5$

D

$4.2$

Solution

(c)

$g_h=g\left[\frac{R}{R+h}\right]^2$

$\Rightarrow g_h=9.8\left[\frac{6400}{6400+480}\right]=8.48 \,m / s ^2$

Standard 11
Physics

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