{81^{(1/{{log }_5}3)}} + {27^{{{log }_{_9}}36 | vedclass

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Question

(d) ${81^{(1/{{\log }_5}3)}} + {27^{{{\log }_9}36}} + {3^{4/{{\log }_7}9}}$

$ = {3^{4{{\log }_3}5}} + {3^{3.{1 \over 2}{{\log }_3}36}} + {3^{4{{\lo

Vedclass · Accepted Answer

$890$

Vedclass · Answer

(d) ${81^{(1/{{\log }_5}3)}} + {27^{{{\log }_9}36}} + {3^{4/{{\log }_7}9}}$

$ = {3^{4{{\log }_3}5}} + {3^{3.{1 \over 2}{{\log }_3}36}} + {3^{4{{\log }_9}7}}$

$ = {3^{{{\log }_3}{5^4}}} + {3^{{{\log }_3}{{36}^{3/2}}}} + {3^{{{\log }_3}{7^{4/2}}}}$

$ = {5^4} + {36^{3/2}} + {7^2} = 890$.

${81^{(1/{{\log }_5}3)}} + {27^{{{\log }_{_9}}36}} + {3^{4/{{\log }_{_7}}9}} = . . . .$

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