Gujarati
3-1.Vectors
easy

दो सदिशों $\mathop A\limits^ \to $ तथा $\mathop B\limits^ \to $ के मध्य कोण $\theta $ हो तो इनके योग का मान होगा

A

$\sqrt {{A^2} + {B^2} + 2AB\cos \theta } $

B

$\sqrt {{A^2} - {B^2} + 2AB\cos \theta } $

C

$\sqrt {{A^2} + {B^2} - 2AB\sin \theta } $

D

$\sqrt {{A^2} + {B^2} + 2AB\sin \theta } $

Solution

As we know,

Resultant of two vectors $\vec{A}$ and $\vec{B}$ is

$R =\sqrt{ A ^2+ B ^2+2 AB \cos \theta}$

Standard 11
Physics

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