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13.Statistics
medium
જો તો વિચરણ $\sigma^2$ =................................
$x_i$ | $0$ | $1$ | $5$ | $6$ | $10$ | $12$ | $17$ |
$f_i$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |
A
$28$
B
$29$
C
$27$
D
$25$
(JEE MAIN-2024)
Solution
$x_i$ | $f_i$ | $f_ix_i$ | $f_ix_i^2$ |
$0$ | $3$ | $0$ | $0$ |
$1$ | $2$ | $2$ | $2$ |
$5$ | $3$ | $15$ | $75$ |
$6$ | $2$ | $12$ | $72$ |
$10$ | $6$ | $60$ | $600$ |
$12$ | $3$ | $36$ | $432$ |
$17$ | $3$ | $51$ | $867$ |
$\sum f_i = 22$ |
$\sum f_ix_i^2 = 2048$ |
$ \therefore \quad \sum \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}=176$
$ \text { So } \overline{\mathrm{x}}=\frac{\sum \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\sum \mathrm{f}_{\mathrm{i}}}=\frac{176}{22}=8 $
$ \text { for } \sigma^2=\frac{1}{\mathrm{~N}} \sum \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}^2-(\overline{\mathrm{x}})^2 $
$ \quad=\frac{1}{22} \times 2048-(8)^2$
$ \quad=93.090964 $
$\quad=29.0909$
Standard 11
Mathematics
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જો આવૃત્તિ વિતરણ
$X_i$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ | $8$ |
Frequency $f_i$ | $3$ | $6$ | $16$ | $\alpha$ | $9$ | $5$ | $6$ |
નું વિચરણ $3$ હોય, તો $\alpha=…………..$