The vertex of a right angle of a right angled triangle lies on the straight line $2x + y - 10 = 0$ and the two other vertices, at points $(2, -3)$ and $(4, 1)$ then the area of triangle in sq. units is

  • A

    $\sqrt{10}$

  • B

    $3$

  • C

    $\frac{33}{5}$

  • D

    $11$

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