Variance of $^{10}C_0$ , $^{10}C_1$ , $^{10}C_2$ ,.... $^{10}C_{10}$ is
$\frac{{10.\,{}^{20}{C_{_{10}}} - {2^{10}}}}{{100}}$
$\frac{{11\,{}^{20}{C_{_{10}}} - {2^{10}}}}{{11}}$
$\frac{{10.\,{}^{20}{C_{_{10}}} - {2^{20}}}}{{100}}$
$\frac{{11.\,{}^{20}{C_{_{10}}} - {2^{20}}}}{{121}}$
If the variance of the following frequency distribution is $50$ then $x$ is equal to:
Class | $10-20$ | $20-30$ | $30-40$ |
Frequency | $2$ | $x$ | $2$ |
The mean and variance of $7$ observations are $8$ and $16,$ respectively. If five of the observations are $2,4,10,12,14 .$ Find the remaining two observations.
In any discrete series (when all values are not same) the relationship between $M.D.$ about mean and $S.D.$ is
The mean life of a sample of 60 bulbs was 650 hours and the standard deviation was 8 hours. A second sample of 80 bulbs has a mean life of 660 hours and standard deviation 7 hours. Find the overall standard deviation.
Mean and standard deviation of 100 items are 50 and $4,$ respectively. Then find the sum of all the item and the sum of the squares of the items.