Angle between overrightarrow P and resultant of (overrightarrow P + overrightarrow Q ) and (overrigh

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3-1.Vectors

easy

What is the angle between $\overrightarrow P $ and the resultant of $(\overrightarrow P + \overrightarrow Q )$ and $(\overrightarrow P - \overrightarrow Q )$

A

Zero

B

${\tan ^{ - 1}}(P/Q)$

C

${\tan ^{ - 1}}(Q/P)$

D

${\tan ^{ - 1}}(P - Q)/(P + Q)$

Solution

(a) Resultant $\vec R = \vec P + \vec Q + \vec P – \vec Q = 2\vec P$

The angle between $\vec P$ and $2\vec P$ is zero.

Standard 11

Physics

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