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1.Relation and Function
easy
આપેલ પૈકી . . . . વિધેયનું વ્યસ્ત વિધેય તે વિધેય જ હોય .
A
$f(x) = \frac{{1 - x}}{{1 + x}}$
B
$f(x) = {5^{\log x}}$
C
$f(x) = {2^{x(x - 1)}}$
D
એકપણ નહી.
Solution
(a) Since $fof(x) = f\,(f(x)\,) = f\left( {\frac{{1 – x}}{{1 + x}}} \right) $
$= \frac{{1 – \frac{{1 – x}}{{1 + x}}}}{{1 + \frac{{1 – x}}{{1 + x}}}} = x,\,\forall x$
$\therefore \,\,\,fof = I\, \Rightarrow \,\,f$ is the inverse of itself.
Standard 12
Mathematics
