Which of the following pairs are not logically equivalent ?
$ \sim \left( { \sim p} \right)$ and $p$
$p\, \vee \,\left( {p\, \wedge \,q} \right)$ and $q$
$ \sim \,\left( {p\, \wedge \,q} \right)$ and $\left( { \sim p} \right)\, \vee \,\left( { \sim q} \right)$
$ \sim \left( { \sim p\, \wedge \,q} \right)$ and $\left( {p\, \vee \, \sim \,q} \right)$
Let $\Delta, \nabla \in\{\wedge, \vee\}$ be such that $p \nabla q \Rightarrow(( p \nabla$q) $\nabla r$ ) is a tautology. Then (p $\nabla q ) \Delta r$ is logically equivalent to
Let $p$ and $q$ denote the following statements
$p$ : The sun is shining
$q$ : I shall play tennis in the afternoon
The negation of the statement "If the sun is shining then I shall play tennis in the afternoon", is
Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F _{2}( A , B )=( A \vee B ) \vee( B \rightarrow \sim A )$ be two logical expressions. Then ...... .
$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ is
Consider the following three statements :
$P : 5$ is a prime number.
$Q : 7$ is a factor of $192$.
$R : L.C.M.$ of $5$ and $7$ is $35$.
Then the truth value of which one of the following statements is true?