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14.Probability
easy
$A$ और $B$ दो घटनाएँ इस प्रकार हैं कि $P ( A )=0.54, P ( B )=0.69$ और $P ( A \cap B )=0.35 .$
ज्ञात कीजिए
$P \left( A ^{\prime} \cap B ^{\prime}\right)$
A
$0.12$
B
$0.12$
C
$0.12$
D
$0.12$
Solution
It is given that $P ( A )=0.54$, $P ( B )=0.69$, $P (A \cap B)=0.35$
$A^{\prime} \cap B^{\prime}=(A \cup B)^{\prime}$ [by De Morgan's law]
$\therefore P \left(A^{\prime} \cap B^{\prime}\right)$ $= P (A \cup B)^{\prime}=1- P (A \cup B)=1-0.88=0.12$
Standard 11
Mathematics
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