frac{2 tan 30^{circ}}{1+tan ^{2} 30^{circ}}= | vedclass

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Question

$\frac{2 	an 30^{\circ}}{1+	an ^{2} 30^{\circ}}$

$=\frac{2\left(\frac{1}{\sqrt{3}}ight)}{1+\left(\frac{1}{\sqrt{3}}ight)^{2}}=\frac{\frac{2}{

Vedclass · Accepted Answer

$\sin 60^{\circ}$

Vedclass · Answer

$\frac{2 	an 30^{\circ}}{1+	an ^{2} 30^{\circ}}$

$=\frac{2\left(\frac{1}{\sqrt{3}}ight)}{1+\left(\frac{1}{\sqrt{3}}ight)^{2}}=\frac{\frac{2}{\sqrt{3}}}{1+\frac{1}{3}}=\frac{\frac{2}{\sqrt{3}}}{\frac{4}{3}}$

$=\frac{6}{4 \sqrt{3}}=\frac{\sqrt{3}}{2}$

Out of the given alternatives, only $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$

$\frac{2 \tan 30^{\circ}}{1+\tan ^{2} 30^{\circ}}=$

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