$\frac{1+\tan ^{2} A}{1+\cot ^{2} A}=........$
$\frac{1+\tan ^{2} A}{1+\cot ^{2} A}=........$
- A
$\sec ^{2} A$
- B
$-1$
- C
$\cot ^{2} A$
- D
$\tan ^{2} A$
Similar Questions
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