frac{{sin 3A - cos left( {frac{pi }{2} - A} r | vedclass

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Question

(d) $\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}}$

$ = \frac{{\sin 3A - \sin A}}{{\cos A - \cos 3A}

Vedclass · Accepted Answer

$\cot 2A$

Vedclass · Answer

(d) $\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}}$

$ = \frac{{\sin 3A - \sin A}}{{\cos A - \cos 3A}}$

$=\frac{{2\cos 2A\sin A}}{{2\sin 2A\sin A}}$

$= \frac{{\cos 2A}}{{\sin 2A}} = \cot 2A$.

$\frac{{\sin 3A - \cos \left( {\frac{\pi }{2} - A} \right)}}{{\cos A + \cos (\pi + 3A)}} = $

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