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$1\, mol$ વાયુની ચક્રીય પ્રક્રિયા આપેલી છે.તો $AB,BC$ અને $CA$ માં થતું કાર્ય
$ 0,\,R{T_2}\ln \left( {\frac{{{V_1}}}{{{V_2}}}} \right)\,,\,R\,({T_1} - {T_2}) $
$ R({T_1} - {T_2}),\,0,\,R{T_1}\ln \frac{{{V_1}}}{{{V_2}}} $
$ 0,\,R{T_2}\ln \left( {\frac{{{V_2}}}{{{V_1}}}} \right)\,,\,R\,({T_1} - {T_2}) $
$ 0,\,R{T_2}\ln \left( {\frac{{{V_2}}}{{{V_1}}}} \right)\,,\,R\,({T_2} - {T_1}) $
Solution
(c) Process $AB$ is isochoric, $\therefore$ ${W_{AB}} = P\,\Delta V = 0$
Process $BC$ is isothermal $\therefore$ ${W_{BC}} = R{T_2}.\ln \left( {\frac{{{V_2}}}{{{V_1}}}} \right)$
Process $CA$ is isobaric
$\therefore {W_{CA}} = – \,P\Delta V$$ = – \,R\Delta T$$ = – \,R({T_1} – {T_2})$$ = R({T_2} – {T_1})$
(Negative sign is taken because of compression)
