A system has basic dimensions as density [D], | vedclass

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Question

$\mathrm{F}=\mathrm{Ma}=$ volume $	imes$ density $	imes\left(\frac{\mathrm{L}}{\mathrm{T}^{2}}ight)$

$=(	ext { Area } 	imes 	ext { length })

Vedclass · Accepted Answer

$[AV^2D]$

Vedclass · Answer

$\mathrm{F}=\mathrm{Ma}=$ volume $	imes$ density $	imes\left(\frac{\mathrm{L}}{\mathrm{T}^{2}}ight)$

$=(	ext { Area } 	imes 	ext { length }) 	imes$ density $	imes \frac{\mathrm{L}}{\mathrm{T}^{2}}$

$\left[	ext { velocity } \mathrm{v}^{2}=\frac{\mathrm{L}^{2}}{\mathrm{T}^{2}}ight]$

$=\left[\mathrm{Av}^{2} \mathrm{D}ight]$

List I	List II
$(i)$ Curie	$(A)$ $ML{T^{ - 2}}$
$(ii)$ Light year	$(B)$ $M$
$(iii)$ Dielectric strength	$(C)$ Dimensionless
$(iv)$ Atomic weight	$(D)$ $T$
$(v)$ Decibel	$(E)$ $M{L^2}{T^{ - 2}}$
	$(F)$ $M{T^{ - 3}}$
	$(G)$ ${T^{ - 1}}$
	$(H)$ $L$
	$(I)$ $ML{T^{ - 3}}{I^{ - 1}}$
	$(J)$ $L{T^{ - 1}}$

A system has basic dimensions as density $[D]$, velocity $[V]$ and area $[A]$. The dimensional representation of force in this system is

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