According to Joule's law of heating, heat | vedclass

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Question

(b) $H = {I^2}R\,t$

$	herefore \,\,\,\frac{{\Delta H}}{H} 	imes 100 = \left( {\frac{{2\Delta I}}{I} + \frac{{\Delta R}}{R} + \frac{{\Delta t}}{t}

Vedclass · Accepted Answer

$ \pm 16\%$

Vedclass · Answer

(b) $H = {I^2}R\,t$

$	herefore \,\,\,\frac{{\Delta H}}{H} 	imes 100 = \left( {\frac{{2\Delta I}}{I} + \frac{{\Delta R}}{R} + \frac{{\Delta t}}{t}} ight) 	imes 100$

$ = (2 	imes 3 + 4 + 6)\% $ $ = 16\% $

According to Joule's law of heating, heat produced $H = {I^2}\,Rt$, where I is current, $R$ is resistance and $t$ is time. If the errors in the measurement of $I, R$ and t are $3\%, 4\% $ and $6\% $ respectively then error in the measurement of $H$ is

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