Consider $\triangle ACB$, right-angled at $C$, in which $AB =29$ units, $BC =21$ units and $\angle ABC =\theta$ (see $Fig.$). Determine the values of
$(i)$ $\cos ^{2} \theta+\sin ^{2} \theta$
$(ii)$ $\cos ^{2} \theta-\sin ^{2} \theta$
Consider $\triangle ACB$, right-angled at $C$, in which $AB =29$ units, $BC =21$ units and $\angle ABC =\theta$ (see $Fig.$). Determine the values of
$(i)$ $\cos ^{2} \theta+\sin ^{2} \theta$
$(ii)$ $\cos ^{2} \theta-\sin ^{2} \theta$
In $\Delta ACB ,$ we have
$AC=\sqrt{ AB ^{2}- BC ^{2}}=\sqrt{(29)^{2}-(21)^{2}}$
$=\sqrt{(29-21)(29+21)}=\sqrt{(8)(50)}=\sqrt{400}=20$ units
So, $\sin \theta=\frac{A C}{A B}=\frac{20}{29}, \cos \theta=\frac{B C}{A B}=\frac{21}{29}$
Now,
$(i)$ $\cos ^{2} \theta+\sin ^{2} \theta=\left(\frac{20}{29}\right)^{2}+\left(\frac{21}{29}\right)^{2}=\frac{20^{2}+21^{2}}{29^{2}}=\frac{400+441}{841}=1$
and
$(ii)$ $\cos ^{2} \theta-\sin ^{2} \theta=\left(\frac{21}{29}\right)^{2}-\left(\frac{20}{29}\right)^{2}=\frac{(21+20)(21-20)}{29^{2}}=\frac{41}{841}$
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