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1.Relation and Function
normal
$f (x)$ = $\sqrt {{{\log }_2}\left( {\frac{{10x - 4}}{{4 - {x^2}}}} \right) - 1} $ નો પ્રદેશગણ મેળવો.
A
$\left[ { - 6, - 2} \right) \cup \left[ {1,2} \right)$
B
$\left[ { - 6,2} \right)$
C
$\left[ { - 6,1} \right)$
D
$\left( { - 2,2} \right)$
Solution

$\log _{2}\left(\frac{10 x-4}{4-x^{2}}\right) \geq 1$
$\Rightarrow \frac{10 x-4}{4-x^{2}}-2 \geq 0 $
$\Rightarrow \frac{x^{2}+5 x-6}{4-x^{2}} \geq 0$
$\Rightarrow \frac{(x+6)(x-1)}{(x-2)(x+2)} \leq 0$
Standard 12
Mathematics