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3 and 4 .Determinants and Matrices
easy
Evaluate $\left|\begin{array}{ccc}102 & 18 & 36 \\ 1 & 3 & 4 \\ 17 & 3 & 6\end{array}\right|$
A
$3$
B
$0$
C
$5$
D
$2$
Solution
Note that $\left|\begin{array}{ccc}102 & 18 & 36 \\ 1 & 3 & 4 \\ 17 & 3 & 6\end{array}\right|=\left|\begin{array}{ccc}6(17) & 6(3) & 6(6) \\ 1 & 3 & 4 \\ 17 & 3 & 6\end{array}\right|=6\left|\begin{array}{ccc}17 & 3 & 6 \\ 1 & 3 & 4 \\ 17 & 3 & 6\end{array}\right|=0$
Standard 12
Mathematics