सारणिकों का मान ज्ञात कीजिए :

$\left|\begin{array}{ll}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right|$

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$\left| {\begin{array}{*{20}{c}}
  {\cos \theta }&{ - \sin \theta } \\ 
  {\sin \theta }&{\cos \theta } 
\end{array}} \right|$

$ = (\cos \theta )(\cos \theta ) - ( - \sin \theta )(\sin \theta )$

$ = {\cos ^2}\theta  + {\sin ^2}\theta $

$ = 1$

Similar Questions

यदि $\alpha ,\beta \ne 0$ तथा $f\left( n \right) = {\alpha ^n} + {\beta ^n}$ तथा

$\left| {\begin{array}{*{20}{c}}3&{1 + f\left( 1 \right)}&{1 + f\left( 2 \right)}\\{1 + f\left( 1 \right)}&{1 + f\left( 2 \right)}&{1 + f\left( 3 \right)}\\{1 + f\left( 2 \right)}&{1 + f\left( 3 \right)}&{1 + f\left( 4 \right)}\end{array}} \right|\;$

$= K{\left( {1 - \alpha } \right)^2}$ ${\left( {1 - \beta } \right)^2}{\left( {\alpha - \beta } \right)^2}$ है, तो $K$ बराबर है

  • [JEE MAIN 2014]

यदि $A = \left| {\,\begin{array}{*{20}{c}}{ - 1}&2&4\\3&1&0\\{ - 2}&4&2\end{array}\,} \right|$and $B = \left| {\,\begin{array}{*{20}{c}}{ - 2}&4&2\\6&2&0\\{ - 2}&4&8\end{array}\,} \right|$,तो $B$ का मान होगा

$\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{1 + x}&1\\1&1&{1 + y}\end{array}\,} \right| = $

सारणिक $\left| {\,\begin{array}{*{20}{c}}1&a&{b + c}\\1&b&{c + a}\\1&c&{a + b}\end{array}\,} \right|$ का मान है

सारणिक $\left| {\,\begin{array}{*{20}{c}}a&b&{a - b}\\b&c&{b - c}\\2&1&0\end{array}\,} \right|$ का मान शून्य होगा यदि $a,b,c$ होंगे