Fill in the blanks in following table :

$P(A)$ $P(B)$ $P(A \cap B)$ $P (A \cup B)$
$0.35$  ........... $0.25$  $0.6$

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Here, $P(A)=0.35$,  $P(A \cap B)=0.25$,  $P(A \cup B)=0.6$

We know that $P (A \cup B)= P ( B )+ P ( B )- P (A \cap B)$

$\therefore $  $0.6=0.35+ P ( B )-0.25$

$\Rightarrow $  $P ( B )=0.6-0.35+0.25$

$\Rightarrow $  $P ( B )=0.5$

Similar Questions

If the odds in favour of an event be $3 : 5$, then the probability of non-occurrence of the event is

$A, B, C$ are any three events. If $P (S)$ denotes the probability of $S$ happening then $P\,(A \cap (B \cup C)) = $

The probability that at least one of $A$ and $B$ occurs is $0.6$. If $A$ and $B$ occur simultaneously with probability $0.3$, then $P(A') + P(B') = $

If $E$ and $F$ are independent events such that $0 < P(E) < 1$ and $0 < P\,(F) < 1,$ then

  • [IIT 1989]

Two balls are drawn at random with replacement from a box containing $10$ black and $8$ red balls. Find the probability that both balls are red.