The given equation is $36 x^{2}+4 y^{2}=144$

It can be written as

$36 x^{2}+4 y^{2}=114$

Or , $\frac{ x ^{2}}{4}+\frac{y^{2}}{36}=1$

Or, $\frac{x^{2}}{2^{2}}+\frac{y^{2}}{6^{2}}=1$        …….. $(1)$

Here, the denominator of $\frac{y^{2}}{6^{2}}$ is greater than the denominator of $\frac{x^{2}}{2^{2}}$

Therefore, the major axis is along the $y-$ axis, while the minor axis is along the $x-$ axis.

On comparing equation $(1)$ with $\frac{ x ^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1,$ we obtain $b =2$ and $a =6$

$\therefore c=\sqrt{a^{2}-b^{2}}=\sqrt{36-4}=\sqrt{32}=4 \sqrt{2}$

Therefore,

The coordinates of the foci are $(0, \,\pm 4 \sqrt{2})$

The coordinates of the vertices are $(0,\,±6)$

Length of major axis $=2 a=12$

Length of minor axis $=2 b=4$

Eccentricity, $e=\frac{c}{a}=\frac{4 \sqrt{2}}{6}=\frac{2 \sqrt{2}}{3}$

Length of latus rectum $=\frac{2 b^{2}}{a}=\frac{2 \times 4}{6}=\frac{4}{3}$