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8. Sequences and Series
easy
गुणोत्तर श्रेणी का योगफल निर्दिष्ट पदों तक ज्ञात कीजिए।
$0.15,0.015,0.0015, \ldots 20$ पदों तक
A
$\frac{1}{6}\left[1-(0.1)^{20}\right]$
B
$\frac{1}{6}\left[1-(0.1)^{20}\right]$
C
$\frac{1}{6}\left[1-(0.1)^{20}\right]$
D
$\frac{1}{6}\left[1-(0.1)^{20}\right]$
Solution
The given $G.P.$ is $0.15,0.015,0.00015 \ldots$
Here, $a=0.15$ and $r=\frac{0.015}{0.15}=0.1$
$S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$
$\therefore S_{20}=\frac{0.15\left[1-(0.1)^{20}\right]}{1-0.1}$
$=\frac{0.15}{0.9}\left[1-(0.1)^{20}\right]$
$=\frac{15}{90}\left[1-(0.1)^{20}\right]$
$=\frac{1}{6}\left[1-(0.1)^{20}\right]$
Standard 11
Mathematics
