For the ellipse 25{x^2} + 9{y^2} - 150x - 90y | vedclass

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Question

(c) Given equation of ellipse is ,

$25{x^2} + 9{y^2} - 150x - 90y + 225 = 0$

$ \Rightarrow $$25\,{(x - 3)^2} + 9{(y - 5)^2} = 225$

$ \Rightar

Vedclass · Accepted Answer

$4\over5$

Vedclass · Answer

(c) Given equation of ellipse is ,

$25{x^2} + 9{y^2} - 150x - 90y + 225 = 0$

$ \Rightarrow $$25\,{(x - 3)^2} + 9{(y - 5)^2} = 225$

$ \Rightarrow $$\frac{{{{(x - 3)}^2}}}{9} + \frac{{{{(y - 5)}^2}}}{{25}}$ = 1. Here $b > a$

$	herefore $ Eccentricity $e = \sqrt {1 - \frac{{{a^2}}}{{{b^2}}}} = \sqrt {1 - \frac{9}{{25}}} $

$ = \sqrt {\frac{{16}}{{25}}} = \frac{4}{5}$.

For the ellipse $25{x^2} + 9{y^2} - 150x - 90y + 225 = 0$ the eccentricity $e = $

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