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5. Continuity and Differentiation
easy
फलन $f(x) = {e^x},a = 0,b = 1$ के लिए मध्यमान प्रमेय में $c$ का मान होगा
A
$log\, x$
B
$\log (e - 1)$
C
$0$
D
$1$
Solution
(b) यहाँ $\frac{{f(b) – f(a)}}{{b – a}} = f'(c)$
==> $\frac{{{e^b} – {e^a}}}{{b – a}} = f'(c)$
==>$\frac{{e – 1}}{{1 – 0}} = {e^c} \Rightarrow c = \log (e – 1)$.
Standard 12
Mathematics