14.Probability
easy

$A$ और $B$ स्वतंत्र घटनाएँ दी गई हैं जहाँ $P ( A )=0.3, P ( B )=0.6$ तो $P ( A$ और $B$ -नहीं $)$ का मान ज्ञात कीजिए।

A

$0.12$

B

$0.12$

C

$0.12$

D

$0.12$

Solution

It is given that $\mathrm{P}(\mathrm{A})=0.3, \,\mathrm{P}(\mathrm{B})=0.6$

Also, $A$ and $B$ are independent events.

$\mathrm{P}(\mathrm{A}$ and not $\mathrm{B})=\mathrm{P}(\mathrm{A} \cap \mathrm{B})^{\prime}$

$=\mathrm{P}(\mathrm{A})-\mathrm{P}(\mathrm{A} \cap \mathrm{B})$

$=0.3-0.18$

$=0.12$

Standard 11
Mathematics

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