4-1.Complex numbers
medium

यदि $\mathrm{z}=\mathrm{x}+\mathrm{i} y, \mathrm{xy} \neq 0$, समीकरण $z^2+i \bar{z}=0$, को संतुष्ट करता है, तो $\left|z^2\right|$ बराबर है :

A

$9$

B

$1$

C

$4$

D

$\frac{1}{4}$

(JEE MAIN-2024)

Solution

$ z^2=-i \bar{z} $

$ \left|z^2\right|=|i \bar{z}|$

$ \left|z^2\right|=|z|$

$ |z|^2-|z|=0$

$ |z|(|z|-1)=0$

$ |z|=0 \text { (not acceptable) } $

$ \therefore|z|=1 $

$ \therefore|z|^2=1$

Standard 11
Mathematics

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