3 and 4 .Determinants and Matrices
easy

જો $\left| {\,\begin{array}{*{20}{c}}{x - 1}&3&0\\2&{x - 3}&4\\3&5&6\end{array}\,} \right| = 0$ તો $x =$

A

$0$

B

$2$

C

$3$

D

$1$

Solution

(d) Given equation reduces to $(x – 1)\,(6x – 38) = 0$

==> $3{x^2} – 22x + 19 = 0 \Rightarrow (x – 1)(3x – 19) = 0$

==> $x = 1,\,19/3$.

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.