3 and 4 .Determinants and Matrices
easy

यदि $\left| {\,\begin{array}{*{20}{c}}{x - 1}&3&0\\2&{x - 3}&4\\3&5&6\end{array}\,} \right| = 0$, तो $x =$

A

$0$

B

$2$

C

$3$

D

$1$

Solution

दिया गया समीकरण है, $(x – 1)\,(6x – 38) = 0$

$\Rightarrow$ $3{x^2} – 22x + 19 = 0 \Rightarrow (x – 1)(3x – 19) = 0$

$\Rightarrow$ $x = 1,\,19/3$.

Standard 12
Mathematics

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