જો $A + B + C = {180^o},$ તો $\frac{{\sin 2A + \sin 2B + \sin 2C}}{{\cos A + \cos B + \cos C - 1}} = $
જો $A + B + C = {180^o},$ તો $\frac{{\sin 2A + \sin 2B + \sin 2C}}{{\cos A + \cos B + \cos C - 1}} = $
- A
$8\,\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
- B
$8\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
- C
$8\,\sin \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
- D
$8\,\cos \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
Similar Questions
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- [IIT 2001]
${\cos ^2}\,{10^o}\,\, - \,\cos \,\,{10^o}\,\cos \,\,{50^o}\, + \,{\cos ^2}\,{50^o}$ ની કિમત ..... થાય.
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$\frac{{4\sin {9^o}\sin {{21}^o}\sin {{39}^o}\sin {{51}^o}\sin {{69}^o}\sin {{81}^o}}}{{\sin {{54}^o}}}$ =
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સમીકરણ ${\sin ^2}\,2\theta + {\cos ^4}\,2\theta = \frac{3}{4}$ ના $\theta \, \in \,\left( {0,\frac{\pi }{2}} \right)$ ના બધા ઉકેલો નો સરવાળો .......... થાય.
સમીકરણ ${\sin ^2}\,2\theta + {\cos ^4}\,2\theta = \frac{3}{4}$ ના $\theta \, \in \,\left( {0,\frac{\pi }{2}} \right)$ ના બધા ઉકેલો નો સરવાળો .......... થાય.
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