If $A + B + C = {180^o},$ then $\frac{{\sin 2A + \sin 2B + \sin 2C}}{{\cos A + \cos B + \cos C - 1}} = $
If $A + B + C = {180^o},$ then $\frac{{\sin 2A + \sin 2B + \sin 2C}}{{\cos A + \cos B + \cos C - 1}} = $
- A
$8\,\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
- B
$8\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
- C
$8\,\sin \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$
- D
$8\,\cos \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$
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If $x = sec\, \phi - tan\, \phi$ & $y = cosec\, \phi + cot\, \phi$ then :
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- [IIT 1985]
The value of $\sin 600^\circ \cos 330^\circ + \cos 120^\circ \sin 150^\circ $ is
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