If A + B + C = {180^o}, then frac{{sin 2A + s | vedclass

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Question

(b) Here ${D^r} = 4\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$

and ${N^r} = 4\sin A\sin B\sin c$ 

$	herefore L.H.S. = \frac{{{N^r}}}

Vedclass · Accepted Answer

$8\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$

Vedclass · Answer

(b) Here ${D^r} = 4\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}$

and ${N^r} = 4\sin A\sin B\sin c$ 

$	herefore L.H.S. = \frac{{{N^r}}}{{{D^r}}}$

and $\sin A = 2\sin \frac{A}{2}\cos \frac{A}{2}$ .

If $A + B + C = {180^o},$ then $\frac{{\sin 2A + \sin 2B + \sin 2C}}{{\cos A + \cos B + \cos C - 1}} = $

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