જો A + B + C = pi ,(A,B,C 0) અને ખૂણો C | vedclass

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Question

(b) $A + B + C = \pi \Rightarrow A + B = \pi - C$

$ \Rightarrow 	an (A + B) = 	an (\pi - C)$

$ \Rightarrow \frac{{	an A + 	an B}}{{1 - 	an

Vedclass · Accepted Answer

$	an A\,	an B < 1$

Vedclass · Answer

(b) $A + B + C = \pi \Rightarrow A + B = \pi - C$ $ \Rightarrow an (A + B) = an (\pi - C)$ $ \Rightarrow \frac{{ an A + an B}}{{1 - an A an C}} = an (\pi - C)$ $ \Rightarrow \frac{{ an A + an B}}{{1 - an A an B}} = - an C$ Now $C$ is an obtuse angle, hence $ \Rightarrow an C < 0 \Rightarrow - an C > 0$ $ \Rightarrow \frac{{ an A + an B}}{{1 - an A an B}} > 0$ $\Rightarrow 1 - an A an B > 0$ $(\because A,B$ are acute angles; $ herefore an A > 0, an B > 0 )$ $ \Rightarrow an A an B < 1$.

જો $A + B + C = \pi \,(A,B,C > 0)$ અને ખૂણો $C$ એ ગુરુકોણ હોય તો

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