If sin theta + cos theta = 1 then the general | vedclass

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Question

(b) $\sin 	heta + \cos 	heta = 1$

$\Rightarrow \frac{1}{{\sqrt 2 }}\sin 	heta + \frac{1}{{\sqrt 2 }}\cos 	heta = \frac{1}{{\sqrt 2 }}$

Divid

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{\pi }{4} - \frac{\pi }{4}$

Vedclass · Answer

(b) $\sin 	heta + \cos 	heta = 1$

$\Rightarrow \frac{1}{{\sqrt 2 }}\sin 	heta + \frac{1}{{\sqrt 2 }}\cos 	heta = \frac{1}{{\sqrt 2 }}$

Dividing by $\sqrt {{1^2} + {1^2}} = \sqrt 2 $, we get

$\sin \left( {	heta + \frac{\pi }{4}} ight) = \frac{1}{{\sqrt 2 }} = \sin \frac{\pi }{4}$

$ \Rightarrow $ $	heta + \frac{\pi }{4} = n\pi + {( - 1)^n}\frac{\pi }{4}$

$\Rightarrow 	heta = n\pi + {( - 1)^n}\frac{\pi }{4} - \frac{\pi }{4}$.

If $\sin \theta + \cos \theta = 1$ then the general value of $\theta $ is

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